DOMを使ってXML文書を解析するJavaのソースコードで、DOMパーサは、クラス org.apache.xerces.parsers.DOMParserで参照している下記のプログラムで、 [Fatal Error] :17:109: The entity name must immediately follow the '&' in the entity reference. org.xml.sax.SAXParseException; lineNumber: 17; columnNumber: 109; The entity name must immediately follow the '&' in the entity reference. のエラーが出てしまって、解決策が分かりかねています。Javaのネットワークプログラミングに詳しい方、御教示願えればと思います。 package nikkei; import java.io.ByteArrayInputStream; import org.apache.xerces.parsers.DOMParser; import org.w3c.dom.Document; import org.w3c.dom.Element; import org.w3c.dom.NodeList; import org.xml.sax.InputSource; public class TwitterSearch { public static void main(String[] args) throws Exception { TwitterSearch search = new TwitterSearch(); search.search("日経ソフトウエア"); } public void search(String keyword) throws Exception { SearchAPIClient client = new SearchAPIClient(); String xml = client.execute(keyword); parse(xml); } private void parse(String xml) throws Exception { DOMParser parser = new DOMParser(); try { parser.parse(new InputSource(new ByteArrayInputStream(xml.getBytes()))); Document doc = parser.getDocument(); NodeList entries = doc.getElementsByTagName("entry"); for (int i = 0; i < entries.getLength(); i++) { String name = null; String tweet = null; Element entry = (Element) entries.item(i); NodeList titleList = entry.getElementsByTagName("title"); if (titleList.getLength() == 1) { tweet = titleList.item(0).getTextContent(); } NodeList authorList = entry.getElementsByTagName("author"); if (authorList.getLength() == 1) { Element author = (Element) authorList.item(0); NodeList nameList = author.getElementsByTagName("name"); if (nameList.getLength() == 1) { name = nameList.item(0).getTextContent(); } } System.out.println(name + "さんのツイート"); System.out.println("\t" + tweet); } } catch (Exception e) { e.printStackTrace(); } } } package nikkei; import org.apache.http.HttpEntity; import org.apache.http.HttpResponse; import org.apache.http.client.HttpClient; import org.apache.http.client.methods.HttpGet; import org.apache.http.impl.client.DefaultHttpClient; import org.apache.http.util.EntityUtils; public class SearchAPIClient { public String execute(String keyword) throws Exception { String url = "https://twitter.com/search?q=" + keyword; HttpClient httpClient = new DefaultHttpClient(); HttpGet httpGet = new HttpGet(url); HttpResponse response = httpClient.execute(httpGet); HttpEntity entity = response.getEntity(); if (entity != null) { return EntityUtils.toString(entity); } else { return null; } } } よろしくお願いいたします。
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